ln(2x+1)=ln(x^2-1)

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Solution for ln(2x+1)=ln(x^2-1) equation:


Simplifying
ln(2x + 1) = ln(x2 + -1)

Reorder the terms:
ln(1 + 2x) = ln(x2 + -1)
(1 * ln + 2x * ln) = ln(x2 + -1)
(1ln + 2lnx) = ln(x2 + -1)

Reorder the terms:
1ln + 2lnx = ln(-1 + x2)
1ln + 2lnx = (-1 * ln + x2 * ln)
1ln + 2lnx = (-1ln + lnx2)

Solving
1ln + 2lnx = -1ln + lnx2

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add 'ln' to each side of the equation.
1ln + ln + 2lnx = -1ln + ln + lnx2

Combine like terms: 1ln + ln = 2ln
2ln + 2lnx = -1ln + ln + lnx2

Combine like terms: -1ln + ln = 0
2ln + 2lnx = 0 + lnx2
2ln + 2lnx = lnx2

Add '-1lnx2' to each side of the equation.
2ln + 2lnx + -1lnx2 = lnx2 + -1lnx2

Combine like terms: lnx2 + -1lnx2 = 0
2ln + 2lnx + -1lnx2 = 0

Factor out the Greatest Common Factor (GCF), 'ln'.
ln(2 + 2x + -1x2) = 0

Subproblem 1

Set the factor 'ln' equal to zero and attempt to solve: Simplifying ln = 0 Solving ln = 0 Move all terms containing l to the left, all other terms to the right. Simplifying ln = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(2 + 2x + -1x2)' equal to zero and attempt to solve: Simplifying 2 + 2x + -1x2 = 0 Solving 2 + 2x + -1x2 = 0 Move all terms containing l to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + 2x + -2 + -1x2 = 0 + -2 Reorder the terms: 2 + -2 + 2x + -1x2 = 0 + -2 Combine like terms: 2 + -2 = 0 0 + 2x + -1x2 = 0 + -2 2x + -1x2 = 0 + -2 Combine like terms: 0 + -2 = -2 2x + -1x2 = -2 Add '-2x' to each side of the equation. 2x + -2x + -1x2 = -2 + -2x Combine like terms: 2x + -2x = 0 0 + -1x2 = -2 + -2x -1x2 = -2 + -2x Add 'x2' to each side of the equation. -1x2 + x2 = -2 + -2x + x2 Combine like terms: -1x2 + x2 = 0 0 = -2 + -2x + x2 Simplifying 0 = -2 + -2x + x2 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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